In: Statistics and Probability
3. Neonatal intensive care units are extremely expensive to operate and maintain. They are critical in caring for babies that are born prematurely. The population of births is normal with a mean of 256 days and a standard deviation of 25 days?
A NICU (the most expensive) are used with babies with that are born at 200 days or less. What percent of births would need the care of a level 1 NICU?
b. In 2007, 16,552 babies were born in Cuyahoga County. Approximately how many babies from Cuyahoga County would have needed the services of a NICU?
4. The GRE is required to be taken by students seeking admission into the College of Urban Affairs graduate programs. In 2008 -2009 the mean quantitative score on the GRE was 504 with a standard deviation of 121.
a. If the college were to require a minimum quantitative score of 600 or above, what percent of the test takers would qualify for admission? (Assume all in the population qualify on all other factors.)
Result:
3. Neonatal intensive care units are extremely expensive to operate and maintain. They are critical in caring for babies that are born prematurely. The population of births is normal with a mean of 256 days and a standard deviation of 25 days?
A NICU (the most expensive) are used with babies with that are born at 200 days or less. What percent of births would need the care of a level 1 NICU?
z value for 200, Z =(200-256)/25 = -2.24
P( x< 200) = P( z < -2.24) = 0.0125
The required percentage =1.25%
b. In 2007, 16,552 babies were born in Cuyahoga County. Approximately how many babies from Cuyahoga County would have needed the services of a NICU?
0.0125*16552 =206.9
Babies from Cuyahoga County would have needed the services of a NICU= 207
4. The GRE is required to be taken by students seeking admission into the College of Urban Affairs graduate programs. In 2008 -2009 the mean quantitative score on the GRE was 504 with a standard deviation of 121.
a. If the college were to require a minimum quantitative score of 600 or above, what percent of the test takers would qualify for admission? (Assume all in the population qualify on all other factors.)
z value for 600, Z =(600-504)/121 = 0.79
P( x>600) = P( z > 0.79) =0.2148
Percent of the test takers would qualify for admission=21.48%