To what Kelvin temperature must 190. mL of a gas at 45.0°C be changed so the...

To what Kelvin temperature must 190. mL of a gas at 45.0°C be changed so the volume will be 570. mL? Assume the pressure and the amount of gas are held constant.

Expert Solution

Initial Final

V1 = 190ml V2 = 570ml

T1 = 45⁰C = 45+273 = 318K T2 =

V1/T1 = V2/T2

T2 = V2T1/V1

= 570*318/190 = 954K >>>>>answer

queen_honey_blossom answered 2 years ago

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