Question

Write a MIPS program that always checks the bit 0 of a memory data at address 0x0BF81234. If it is equal to one add n^th and (n+1)^th elements of an array and store it to memory address 0x0BF85678 . Suppose $t0 contains the address of the 0^th element of an array of 32-bit data and $t1 = n.

Answer 1

Greetings!!

Code:

li $s0,0x0BF81234                 #address given

lw $t0,0($s0)                          #load word from the given address

andi $t2,$t0,0x00000001        #check whether the LSB is 1

bne $t2,1,done                        #if the LSB is 0, goto label done

mul $t1,$t1,4                          #if the LSB is 1, calculate the offset of nth element

add $s0,$s0,$t1                       #calculate the address of the nth element

lw $t3,0($s0)                          #read the nth element

lw $t4,4($s0)                          #read the n+1 th element

add $t3,$t3,$t4                        #add nth and n+1 th elements

li $s0,0x0BF85678                 #load the given destination address

sw $t3,0($s0)                          #store the sum to the given address

done:

addi $v0,$0,10                        #termination

syscall

Hope this helps