In: Math
Suppose a flop is said to "have a flush draw possibility" if it contains exactly two cards of the same suit, plus another card of a different suit. For instance, A♥ K♥ 10♠ would have a flush draw possibility, but A♥ K♦ 10♠ would not, and also A♥ K♥ 10♥ would not. What is the probability that the flop has a flush draw possibility?
A deck of 52 cards has 4 suits, Spades, Clubs, Diamonds and Hearts
There are 13 cards in each suit, from 2 till 10, the 3 face cards J, Q, K and finally Ace.
Therefore there are 4 cards of each type i.e 4 kings, 4 queens etc
Probability = Favourable Outcomes / Total Outcomes
Please note nCx = n! / [(n-x)!*x!]
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Total Outcomes= Choosing 3 cards out of 52 in 52C3 ways = 22100
First we choose a suit among the 4 from which we get 2 cards (of that suit) = 4C1 = 4 ways
Then we choose 2 cards out of 13 from the chosen suit = 13C2 = 78 ways
Then we choose a suit among the remaining 3 from which we get 1 cards (of that suit) = 3C1 = 3 ways
Then we choose 1 card out of 13 from the chosen suit = 13C1 = 13 ways
Therefore total favourable outcomes = 4 * 78 * 3 * 13 = 12168
Therefore the probability = 12168/22100 = 234 / 425 = 0.5506
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