In: Statistics and Probability
P(z<Z) table :
for composite scores :
top 10.2% : P(z>Z) = 0.102
P(z<Z) = 1-0.102 = 0.898
find z form the table :
z = 1.27
therefore,
for composite score the student's score must be atleast 1.27 standard deviatons more than the mean score
for Math or English scores on either test :
top 4.09% : P(z>Z) = 0.0409
P(z<Z) = 1-0.0409 = 0.9591
find z form the table :
z = 1.74
therefore,
for Math or English scores on either test the student's
score must be atleast 1.74 standard deviatons more than the mean
score
Guidelines that evaluators use to quickly look at applications : 1. For composite score the student's score must be atleast 1.27 standard deviatons more than the mean score 2. For Math or English scores on either test the student's score must be atleast 1.74 standard deviatons more than the mean score |
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