Question

In: Chemistry

what mass of KCl in grams must be added to 500 ml of a 0.15 M...

what mass of KCl in grams must be added to 500 ml of a 0.15 M KCl solution to produce a 0.40 M solution

Solutions

Expert Solution

no of moles of KCl   = molarity * volume in L

                                 = 0.15*0.5   = 0.075 moles

no of moles of KCl   = molarity * volume in L

                                 = 0.4*0.5    = 0.2 moles

no of moles of KCl is added = 0.2-0.075    = 0.125 moles

mass of KCl   = no of moles * gram molar mass

                        = 0.125*74.5   = 9.3125 g of KCl>>>>answer

9.3125g of KCl is added


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