In: Chemistry
what mass of KCl in grams must be added to 500 ml of a 0.15 M KCl solution to produce a 0.40 M solution
no of moles of KCl = molarity * volume in L
= 0.15*0.5 = 0.075 moles
no of moles of KCl = molarity * volume in L
= 0.4*0.5 = 0.2 moles
no of moles of KCl is added = 0.2-0.075 = 0.125 moles
mass of KCl = no of moles * gram molar mass
= 0.125*74.5 = 9.3125 g of KCl>>>>answer
9.3125g of KCl is added