Question

In: Statistics and Probability

Assume that the population distribution of BMI among adults over 18 is Normal with mean μ = 38 and standard deviation σ = 12 and suppose the you have an SRS of 4 adults

Assume that the population distribution of BMI among adults over 18 is Normal with mean μ = 38 and standard deviation σ = 12 and suppose the you have an SRS of 4 adults. What is the probability that your sample will have a mean BMI of 53 or greater? Use Table A: Standard Normal Table and round your answer to 4 decimal places.

Solutions

Expert Solution

 

Given that,

mean = μ = 38

standard deviation = = 12

n = 4

= μ = 38

= / n = 12 / 4 = 6

P( > 53) = 1 - P( < 53)

= 1 - P[( - ) / < (53 - 38) / 6]

= 1 - P(z < 2.5)

Using z table,    

= 1 - 0.9938

= 0.0062


Related Solutions

Given a normal distribution with (mean) μ= 50 and (standard deviation) σ = 4, what is...
Given a normal distribution with (mean) μ= 50 and (standard deviation) σ = 4, what is the probability that NOTE: I'd like to learn how to do this in the shortest way possible on ti 84 plus calculator. a) x>43 b) x<42 c) x>57.5 d) 42 <x<48 e) x<40 or x>55 f) 5% of the values are less than what X value? g) 60% of the values are between what two X values (symmetrically distributed around the mean)? h) 85%...
Suppose x has a normal distribution with mean μ = 57 and standard deviation σ =...
Suppose x has a normal distribution with mean μ = 57 and standard deviation σ = 12. Describe the distribution of x values for sample size n = 4. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 16. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 100. (Round σx to two decimal places.) μx...
Suppose x has a normal distribution with mean μ = 55 and standard deviation σ =...
Suppose x has a normal distribution with mean μ = 55 and standard deviation σ = 7. Describe the distribution of x values for sample size n = 4. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 16. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 100. (Round σx to two decimal places.) μx...
Suppose x has a normal distribution with mean μ = 36 and standard deviation σ =...
Suppose x has a normal distribution with mean μ = 36 and standard deviation σ = 5. Describe the distribution of x values for sample size n = 4. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 16. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 100. (Round σx to two decimal places.) μx...
Suppose x has a normal distribution with mean μ = 52 and standard deviation σ =...
Suppose x has a normal distribution with mean μ = 52 and standard deviation σ = 9. Describe the distribution of x values for sample size n = 4. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 16. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 100. (Round σx to two decimal places.) μx...
Suppose x has a normal distribution with mean μ = 32 and standard deviation σ =...
Suppose x has a normal distribution with mean μ = 32 and standard deviation σ = 12. Describe the distribution of x values for sample size n = 4. (Round σx to two decimal places.) μx = Incorrect: Your answer is incorrect. σx = Describe the distribution of x values for sample size n = 16. (Round σx to two decimal places.) μx = σx = Describe the distribution of x values for sample size n = 100. (Round σx...
Suppose x has a normal distribution with mean μ = 28 and standard deviation σ =...
Suppose x has a normal distribution with mean μ = 28 and standard deviation σ = 4. a) Describe the distribution of x values for sample size n = 4. (Round σx to two decimal places.) μx = σx = b) Describe the distribution of x values for sample size n = 16. (Round σx to two decimal places.) μx = σx = c) Describe the distribution of x values for sample size n = 100. (Round σx to two...
A normal population has mean μ = 55 and standard deviation σ = 8 . What...
A normal population has mean μ = 55 and standard deviation σ = 8 . What is the 85 th percentile of the population?
A population has a mean of μ = 70 and a standard deviation of σ =...
A population has a mean of μ = 70 and a standard deviation of σ = 12 For the same population, find the score (X value) that corresponds to each of the following z-scores. z = 0.50: X=_____                        z = 1.50: X=_____      z = -2.50: X=_____ z = -0.25: X=_____                      z = -0.50: X=_____    z = 1.25: X=_____ A sample has a mean of M = 30 and a standard deviation of s = 7. Find the z-score...
Now assume you have a normal distribution with a mean of 100 and standard deviation of...
Now assume you have a normal distribution with a mean of 100 and standard deviation of 15 that is composed of 2000 participants. Please answer the following questions, what is the probability of the following? (please with steps) a. A score being between 100 and 115 b. A score greater than 130 c. A score less than 70 d. A score either greater than 130 or less than 70 e. A score either greater the 100 or less than 85
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT