Question

In: Statistics and Probability

A sample containing years to maturity and yield for  corporate bonds are contained in the data given...

A sample containing years to maturity and yield for  corporate bonds are contained in the data given below.

Years to Maturity Yield Years to Maturity Yield
5.75 7.728 3.25 2.820
25.25 2.415 5.25 4.835
1.75 5.382 15.75 6.905
23.50 5.106 1.50 4.849
26.25 1.576 23.75 5.054
18.50 7.145 2.50 3.966
20.50 0.811 14.25 5.300
29.75 4.275 16.50 3.114
1.50 7.320 24.75 5.949
5.75 8.140 11.50 2.934
13.50 5.170 21.50 6.921
14.50 7.286 27.75 7.810
13.25 3.505 14.25 6.998
6.25 7.009 12.00 7.759
13.75 7.062 14.00 3.196
10.75 7.764 27.50 1.789
12.75 7.687 17.75 8.066
29.50 1.145 22.75 3.984
6.75 1.055 13.25 3.992
28.25 5.902 17.00 0.794

a. What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation?

Mean (to 4 decimals)
Standard deviation (to 4 decimals)

b. Develop a  confidence interval for the population mean years to maturity. Round the answer to four decimal places.

  ,   years

c. What is the sample mean yield on corporate bonds and what is the sample standard deviation?

Mean (to 4 decimals)
Standard deviation (to 4 decimals)

d. Develop a  confidence interval for the population mean yield on corporate bonds. Round the answer to four decimal places.

  ,   percent

Solutions

Expert Solution

Years to Maturity Yield
Mean 15.3625 Mean 5.01295
Standard Error 1.352465 Standard Error 0.366903
Median 14.25 Median 5.138
Mode 5.75 Mode #N/A
Standard Deviation 8.553742 Standard Deviation 2.320498
Sample Variance 73.16651 Sample Variance 5.384711
Kurtosis -1.01337 Kurtosis -1.09878
Skewness 0.019778 Skewness -0.35711
Range 28.25 Range 7.346
Minimum 1.5 Minimum 0.794
Maximum 29.75 Maximum 8.14
Sum 614.5 Sum 200.518
Count 40 Count 40
  • a) Sample mean years to maturity

  • Mean=15.3625

  • Sample standard deviation years to maturity

  • Std DEv= 8.553742

b) : Population mean years to maturity.

Since population standard deviation is not known. We use t distribution to find confidence interval for population mean.

The 95% confidence interval for population mean years is to maturity is

Alpha: level of significance = 0.05

From t-table

Hence 95% confidence interval is

=(15.3625 -8.553742*2.0227/sqrt(40) ,15.3625 -8.553742*2.0227/sqrt(40))

=(12.6269,18.0981)

95% confidence interval for population mean years to maturity is (12.6269,18.0981) years.

c) Sample mean yield on corporate bond

5.01295

Sample standard deviation yield on corporate bond

2.320498

d) : Population mean yield on corporate bond

Since population standard deviation is not known. We use t distribution to find confidence interval for population mean.

The 95% confidence interval for population mean yield on corporate bond is

Alpha: level of significance = 0.05

From t-table

Hence 95% confidence interval is

=(5.01295 -2.320498*2.0227/sqrt(40) ,5.01295 +2.320498*2.0227/sqrt(40))

=(4.2708,5.7551)

95% confidence interval for population mean yield on corporate bond is (4.2708,5.7551) percent.


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