In: Statistics and Probability
The average annual wind speed in Rochester, Minnesota is 13.1 miles per hour. A sample of 100 days is used to determine the average wind speed. Find the 98% confidence interval of the mean. Assume the standard deviation was 2.8 miles per hour.
Solution :
Given that,
Point estimate = sample mean = =
=13.1
Population standard deviation =
= 2.8
Sample size = n =100
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
Z/2 = Z0.01 = 2.326 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 2.326 * ( 2.8 / 100
)
= 0.65
At 98% confidence interval mean
is,
- E < < + E
13.1 - 0.65 <
< 13.1 + 0.65
12.45 <
< 13.75