Problem 2
A random sample of 41 business days, from 2016 through 2017, of
the closing...
Problem 2
A random sample of 41 business days, from 2016 through 2017, of
the closing price of Apple stock is conducted. The sample produces
an average closing price of $116.16 with a standard deviation of
$10.27.
Verify the requirements for the confidence interval.
For a 95% confidence interval, find the margin of error for the
true average closing price of Apple stock from 2016 through
2017.
Interpret a 95% confidence interval for the true average
closing price of Apple stock from 2016 through 2017.
Respond to the statement that the true average closing price of
Apple stock from 2016 through 2017 was less than $125 . Make your
response understandable to someone not in the class
From a random sample of 75 business days from January 4, 2010,
through February 24, 2017, Russian silver prices had a mean of
$3,338.48 and σ=$205.61 was the population standard deviation of
silver prices. Construct a 90% confidence interval for the true
population mean µ and interpret this interval.
From a random sample of 75 business days from January 4, 2010,
through February 24, 2017, Russian silver prices had a mean of
$3,338.48 and σ=$205.61 was the population standard deviation of
silver prices. µ [?- E. ?=E what is the probability that µ is
contained in the interval?
A statistics practitioner took a random sample of 41
observations from a population whose standard deviation is 29 and
computed the sample mean to be 96.
Note: For each confidence interval, enter your
answer in the form (LCL, UCL). You must include the parentheses and
the comma between the confidence limits.
A. Estimate the population mean with 95% confidence.
Confidence Interval =
B. Estimate the population mean with 95% confidence, changing
the population standard deviation to 52;
Confidence Interval =...
A statistics practitioner took a random sample of 41
observations from a population whose standard deviation is 29 and
computed the sample mean to be 96.
Note: For each confidence interval, enter your
answer in the form (LCL, UCL). You must include the parentheses and
the comma between the confidence limits.
A. Estimate the population mean with 95% confidence.
Confidence Interval =
B. Estimate the population mean with 95% confidence, changing
the population standard deviation to 52;
Confidence Interval =...
Suppose a simple random sample of size n=41 is obtained from a
population with mu=61 and sigma=19.
(b) Assuming the normal model can be used, determine
P(x overbarx < 71.4).
(c) Assuming the normal model can be used, determine
P(x overbarx ≥ 69.1).
The following are closing prices of Google stock for a sample of
trading days. Use the 1-Var Stats command in the TI-84 PLUS
calculator to compute the sample standard deviation. 455.21 ,
482.37, 483.19, 459.63, 497.99, 475.10, 472.08, 444.95, 489.22
Write only a number as your answer. Round to two decimal places
(for example 8.32). Your Answer:
in
a random sample of 41 criminals convicted of a certain crime, it
was determined that the mean length of sentencing was 65 monghs.
with a standard deviation of 7 months. construct and interpret a
95% confidence interval for the mean length of sentencing for this
crime.
a) 95% of the sentences for the crime are between ___ and ___
months
b) one can be 95% confident that the mean length if sentencing
fir this crime is between __ and...
(a). A simple random sample of 37 days was selected. For these
37 days, Parsnip was fed seeds on 22 days and Parsnip was fed
pellets on the other 15 days. The goal is to calculate a 99%
confidence interval for the proportion of all days in which Parsnip
was fed seeds, and to do so there are two assumptions. The first is
that there is a simple random sample, which is satisfied. What is
the second assumption, and specific...
(a). A simple random sample of 37 days was selected. For these
37 days, Parsnip was fed seeds on 20 days and Parsnip was fed
pellets on the other 17 days. The goal is to calculate a 95%
confidence interval for the proportion of all days in which Parsnip
was fed seeds, and to do so there are two assumptions. The first is
that there is a simple random sample, which is satisfied. What is
the second assumption, and specific...
(a). A simple random sample of 37 days was selected. For these
37 days, Parsnip was fed seeds on 22 days and Parsnip was fed
pellets on the other 15 days. The goal is to calculate a 99%
confidence interval for the proportion of all days in which Parsnip
was fed seeds, and to do so there are two assumptions. The first is
that there is a simple random sample, which is satisfied. What is
the second assumption, and specific...