In: Statistics and Probability
Suppose a simple random sample of size n=41 is obtained from a population with mu=61 and sigma=19.
(b) Assuming the normal model can be used, determine
P(x overbarx < 71.4).
(c) Assuming the normal model can be used, determine
P(x overbarx ≥ 69.1).
Solution :
Given that,
mean = = 61
standard deviation = = 19
n = 41
= = 61
a) = / n = 19 / 41 = 2.97
P( > 71.4) = 1 - P( < 71.4)
= 1 - P[( - ) / < (71.4 - 61) / 2.97]
= 1 - P(z < 3.50)
Using z table,
= 1 - 0.9998
= 0.0002
b) P( 69.1 ) = P(( - ) / (69.1 - 61) / 2.97 )
= P(z 2.72)
Using z table
= 0.9967