In: Statistics and Probability
In order to use a 90% confidence interval to compare admission exam scores for sophomores (group #1) and freshmen (group #2), two independent random samples were selected. The results showed:
1-Sophomores: Sample mean = 85, sample standard deviation = 10, sample size = 50.
2-Freshmen: Sample mean = 78, sample standard deviation = 12, sample size = 72.
For forming a 90% confidence interval for μ 1 − μ 2, the standard error is __________ .
Group of answer choices
12
2
None of the other choices represent a suitable response.
10
4
using excel>addin>phstat<two sample test
we have
Pooled-Variance t Test for the Difference Between Two Means | |
(assumes equal population variances) | |
Data | |
Hypothesized Difference | 0 |
Level of Significance | 0.1 |
Population 1 Sample | |
Sample Size | 50 |
Sample Mean | 85 |
Sample Standard Deviation | 10 |
Population 2 Sample | |
Sample Size | 72 |
Sample Mean | 18 |
Sample Standard Deviation | 12 |
standard error | 2.066671 |
Intermediate Calculations | |
Population 1 Sample Degrees of Freedom | 49 |
Population 2 Sample Degrees of Freedom | 71 |
Total Degrees of Freedom | 120 |
Pooled Variance | 126.0333 |
Difference in Sample Means | 67 |
t Test Statistic | 32.41928 |
Two-Tail Test | |
Lower Critical Value | -1.65765 |
Upper Critical Value | 1.657651 |
p-Value | 3.32E-61 |
Reject the null hypothesis |
For forming a 90% confidence interval for μ 1 − μ 2, the standard error is 2.066 ~2