Question

In: Math

The Twister Roller Coaster always has a long line of thrill seekers waiting to take a...

The Twister Roller Coaster always has a long line of thrill seekers waiting to take a ride on it. A random sample of 60 riders waited in line a mean time of 42 minutes with a standard deviation of 12 minutes. Find a 90% confidence interval for the population mean waiting time in the Twister line.

Expert Solution

Solution:

Given that:

= 42 minutes

s = 12 minutes

n = 60

Degrees of freedom = df = n - 1 =60 - 1 = 59

At 90% confidence level the t is ,

= 1 - 90% = 1 - 0.90 = 0.1

/ 2 = 0.1 / 2 = 0.05

t_/2,df = t_0.05,59 = 1.671

Margin of error = E = t_/2,df * (s / $\sqrt$ n)

= 1.671 * ( 12/ $\sqrt$ 60)

= 2.5887

The 90% confidence interval estimate of the population mean is,

- E < < + E

42 - 2.5887 < < 42 + 2.5887

39.4113 < < 44.5887

(39.4113,44.5887)

milcah answered 1 year ago

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