what concentration of cl- results when 745 ml of 0.515 M LiCl is mixed with 679...

what concentration of cl- results when 745 ml of 0.515 M LiCl is mixed with 679 mL 0f 0.443 M MgCl2

Expert Solution

no of moles of LiCl = molarity * volume in ml

= 0.515*745 = 383.675mmoles

LiCl--------> Li^+ + Cl^-

383.675mmoles 383.675mmoles

no of mmoles = 383.675mmoles of Cl^-

no of moles of MgCl2 = molarity * volume in ml

= 0.443*679 = 300.787mmoles

MgCl2 ------------------> Mg^+2 + 2Cl^-

300.787mmoles 2*300.787mmoles

mmoles = 601.574mmoles of Cl^-1

resultant conc of Cl^- = 383.675 +601.574/745+679 = 985.249/1424 = 0.69 M of Cl^-

queen_honey_blossom answered 2 years ago

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