Question

In: Math

2. Consider the following data: x= 1, 2, 3, 4, 5 y =3, 2, 4, 6,...

2. Consider the following data:

x= 1, 2, 3, 4, 5

y =3, 2, 4, 6, 5

By hand, not using Matlab, and showing your work:

(a) Compute the correlation coefficient.

(b) Find the least-squares line.

(c) Find the standard deviation around the least-squares line.

Solutions

Expert Solution

(a) The correlation coefficient is 0.8.

(b) The least-squares line is:

y = a + bx = 1.6 + 0.8x

(c) Standard deviation = 1.58

The calculations are:

x y (x-xMean) (y-yMean) (x-xMean)*(y-yMean) (x-xMean)² zx zy zx*zy
1 3 -2 -1 2 4 -1.26491 -0.63246 0.8
2 2 -1 -2 2 1 -0.63246 -1.26491 0.8
3 4 0 0 0 0 0 0 0
4 6 1 2 2 1 0.632456 1.264911 0.8
5 5 2 1 2 4 1.264911 0.632456 0.8
Mean 3 4 0 0 8 10 3.2
Std Dev. 1.581139 1.581139
b 0.8
a 1.6
r 0.8

The formulas are:

Correlation coefficient = zx*zy/n-1 n = 5 in this case


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