In: Math
The median US salary is $50,700, according to US Census data. Using a one-sample
t-test, test to see if participant income (INC1) is different from the national average. Use a two-tailed test and an alpha level of 5%.
One-Sample Statistics
INCOME N=400 Mean=$47,112.92 Std. Deviation=$40,477.089 Std. Error Mean=$2,023.854
One-Sample Test
Test Value = 0
INCOME t=23.279 df=399 Sig. (2-tailed)=.000 Mean Difference=$47,112.920
95% Confidence Interval of the Difference
(lower)$43,134.17 (higher)$51,091.67
The median US salary is $50,700, according to US Census data. Using a one-sample
t-test, test to see if participant income (INC1) is different from the national average. Use a two-tailed test and an alpha level of 5%.
One-Sample Statistics
INCOME N=400 Mean=$47,112.92 Std. Deviation=$40,477.089 Std. Error Mean=$2,023.854

|
t Test for Hypothesis of the Mean |
|
|
Data |
|
|
Null Hypothesis m= |
50700 |
|
Level of Significance |
0.05 |
|
Sample Size |
400 |
|
Sample Mean |
47112.92 |
|
Sample Standard Deviation |
40477.089 |
|
Intermediate Calculations |
|
|
Standard Error of the Mean |
2023.8545 |
|
Degrees of Freedom |
399 |
|
t Test Statistic |
-1.7724 |
|
Two-Tail Test |
|
|
Lower Critical Value |
-1.9659 |
|
Upper Critical Value |
1.9659 |
|
p-Value |
0.0771 |
|
Do not reject the null hypothesis |
|
Calculated t= -1.7724, P=0.0771 which is > 0.05 level of significance.
Ho is not rejected.
Participant income is not significantly different from the national average
95% CI for difference
|
lower limit |
-7565.83071 |
|
Upper limit |
391.6707062 |