In: Statistics and Probability
solution
given that
P(X<73.3 ) = P[(X- ) / < (73.3-70) /10 ]
= P(z <0.33 )
Using z table
=0.6293
probability=0.629
(B)
n = 50
= 1035
= / n= 201/ 50 =28.4257
P(1050< <1065 ) = P[(1050-1035) / 28.4257< ( - ) / < (1065-1035) / 28.4257)]
= P( 0.53< Z <1.06 )
= P(Z <1.06 ) - P(Z <0.53 )
Using z table
=0.8554-0.7019
=0.1535
probability= 0.1535