In: Statistics and Probability
solution
given that
P(X<73.3 ) = P[(X-
) /
<
(73.3-70) /10
]
= P(z <0.33 )
Using z table
=0.6293
probability=0.629
(B)
n = 50
= 1035
=
/
n= 201/
50 =28.4257
P(1050< <1065
) = P[(1050-1035) / 28.4257< (
-
) /
< (1065-1035) / 28.4257)]
= P( 0.53< Z <1.06 )
= P(Z <1.06 ) - P(Z <0.53 )
Using z table
=0.8554-0.7019
=0.1535
probability= 0.1535