Question

In: Chemistry

Calculate the pH of the solution when the following substances are added together 200 mL of...

Calculate the pH of the solution when the following substances are added together

200 mL of 0.1 M NaOH and 80 mL of 2.5 M Acetic Acid

200 mL of 0.1 M NaOH and 8 mL of 0.25M Acetic Acid

Solutions

Expert Solution

no of moles of NaOH = molarity* volume in L

                                   = 0.1*0.2   = 0.02moles

no of moles of CH3COOH = molarity * volume in L

                                         = 2.5*0.08   = 0.2moles

               CH3COOH + NaOH ----------> CH3COONa + H2O

I              0.2               0.02                       0         

C           -0.02             -0.02                      0.02

E           0.18               0                           0.02

          PH   =   PKa + log[CH3COONa]/[CH3COOH]

                  = 4.75 + log0.02/0.18

2.

no of moles of NaOH = molarity* volume in L

                                   = 0.1*0.2   = 0.02moles

no of moles of CH3COOH = molarity * volume in L

                                         = 0.25*0.008   = 0.002moles

             CH3COOH + NaOH ----------> CH3COONa + H2O

I              0.002              0.02                       0         

C           -0.002             -0.002                    0.002

    remaining no of moles of NaOH = 0.02-0.002 = 0.018 moles

                   molarity of OH- = no of moles/total volume in L

                                             = 0.018/0.208   = 0.0865M

    POH    = -log[OH-]

               = -log0.0865 = 1.0629

PH    = 14-POH

          = 14-1.0629   = 12.9371


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