Question

In java Write a static method named consecutiveDigits that accepts an integer n as a parameter and that returns the highest number of consecutive digits in a row from n that have the same value. For example, the number 3777785 has four consecutive occurrences of the number 7 in a row, so the call consecutiveDigits(3777785) should return 4.

For many numbers the answer will be 1 because they don't have any adjacent digits that match. Below are sample calls on the method. You are not allowed to use a String to solve this problem. You may assume that the value passed to the method is greater than or equal to 0.

consecutiveDigits(99) will return 2

consecutiveDigits(1) will return 1

consecutiveDigits(11335577) will return 2

consecutiveDigits(12345) will return 1

consecutiveDigits(89995) will return 3

Answer 1

Sample output:

The screenshots are attached below for reference.

Please follow them for proper output.

Program to copy:

import java.util.*;
public class Main
{
public static int consecutiveDigits(int n){
String s;
s=Integer.toString(n);
int c=1,temp=1;
for(int i=0;i<s.length()-1;i++){//iterate through all the numbers
if(s.charAt(i)==s.charAt(i+1)){//check if same or not
temp++;//increment temp if same consecutiveDigits occurs
if(s.length()==2)
return temp;
}
else{
if(c<temp){//check if current count is maximum
c=temp;
temp=1;
}
else
temp=1;
}
}
return c;//return maximum coutn obtained
}
   public static void main(String[] args) {
       Scanner inp=new Scanner(System.in);
       int num;
       String n;
       System.out.println("Enter number:");//read number from user
       num=inp.nextInt();
       int res=consecutiveDigits(num);//call the function
       System.out.println("The maximum consecutive same value count is:"+res);//print the returned value
      
   }
}

Note:

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