In: Math
For homes in a certain state, electric consumption amounts last year approximately followed a mound-shaped (normal) distribution with a mean of 1034 kilowatt-hours and a standard deviation of 182 kilowatt-hours.
(a) According to the empirical rule, approximately 99.7% of
values in the distribution will be between these two bounds:
Lower-bound =___ kilowatt-hours and upper-bound = ___
kilowatt-hours.
(b) According to the empirical rule, approximately 68% of values
in the distribution will be between these two bounds:
Lower-bound = ___ kilowatt-hours and upper-bound = ___
kilowatt-hours.
(c) According to the empirical rule, approximately 95% of values
in the distribution will be between these two bounds:
Lower-bound = ___ kilowatt-hours and upper-bound =
___kilowatt-hours.
Solution :
Given that ,
mean = = 1034 kilowatt-hours
standard deviation = = 182 kilowatt-hours
Using Empirical rule,
a) P( - 3 < x < + 3 ) = 99.7%
= P( 1034 - 3 * 182 < x < 1034 + 3 * 182 ) = 99.7%
= P( 1034 - 546 < x < 1034 + 546 ) = 99.7%
=P( 488 < x < 1580 ) = 99.7%
Lower-bound = 488 kilowatt-hours and upper-bound = 1580 kilowatt-hours.
b) P( - < x < + ) = 68%
= P( 1034 - 182 < x < 1034 + 182 ) = 68%
= P( 852 < x < 1216 ) =68%
Lower-bound = 852 kilowatt-hours and upper-bound = 1216 kilowatt-hours.
c) P( - 2 < x < + 2 ) = 95%
= P( 1034 - 2 * 182 < x < 1034 + 2 * 182 ) = 95%
= P( 1034 - 364 < x < 1034 + 364 ) = 95%
=P( 670 < x < 1398 ) = 95%
Lower-bound = 670 kilowatt-hours and upper-bound = 1398 kilowatt-hours.