Butyric acid, HC4H7O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of calcium butyrate,...

Butyric acid, HC4H7O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of calcium butyrate, a food supplement. What is the hydronium ion concentration (in M) and pH in a 0.681 M solution of HC4H7O2? (Assume Kw = 1.01 ✕ 10−14.)

hydronium ion

M?

pH?

Expert Solution

HC4H7O2 ---------------> H^+ + C4H7O2^-

I 0.681 0 0

C -x +x +x

E 0.681-x +x +x

Ka =[ H^+] [C4H7O2^-]/[HC4H7O2]

1.5*10^-5 = x*x/0.681-x

1.5*10^-5*(0.681-x) = x^2

x = 0.0032

[H^+] = x = 0.0032M

PH = -log[H+]

= -log0.0032 = 2.4948 >>>>answer

queen_honey_blossom answered 2 years ago

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