Question

The following information is given for mercury, Hg, at 1atm:

boiling point = 357 °C	Hvap(357 °C) = 59.3 kJ/mol
specific heat liquid = 0.139 J/g°C

At a pressure of 1 atm, what is H in kJ for the process of condensing a 46.3 g sample of gaseous mercury at its normal boiling point of 357 °C.

kJ

The following information is given for ether, C₂H₅OC₂H₅, at 1atm:

boiling point = 34.6 °C	Hvap(34.6 °C) = 26.5 kJ/mol
specific heat liquid = 2.32 J/g°C

At a pressure of 1 atm,  kJ of heat are needed to vaporize a 41.0 g sample of liquid ether at its normal boiling point of 34.6 °C.

Answer 1

Given Data is,

Q) The following information is given for mercury, Hg, at 1atm: boiling point = 357 °C Hvap(357 °C) = 59.3 kJ/mol specific heat liquid = 0.139 J/g°C At a pressure of 1 atm, what is H in kJ for the process of condensing a 46.3 g sample of gaseous mercury at its normal boiling point of 357 °C. kJ

boiling point = 357 °C

Hvap(357 °C) = 59.3 kJ/mol

Amount of Hg = 46.3 g

Number of moles = amount in g / molar mass

= 46.3 g/ 200.6 g/ mole Hg

= 0.23080 mole Hg

Delta H = ( number of moles ) ( - Delta hvap )

=0.23080 mole Hg*(-59.3 kJ/mol)

Delta H = -13.6844 KJ.

Q) The following information is given for ether, C2H5OC2H5, at 1atm:boiling point = 34.6 °C Hvap(34.6 °C) = 26.5 kJ/mol specific heat liquid = 2.32 J/g°C /At a pressure of 1 atm, kJ of heat are needed to vaporize a 41.0 g sample of liquid ether at its normal boiling point of 34.6 °C

mass of liquid ether = 41.0 g

moles of ether = 41.0 / 74 = 0.5540

delta H vap = 26.5 kJ/mol

Q = - n x delta H vap

= - 0.5540 mol x (-26.5 kJ/mol)

= 14.681 kJ

heat needed to vapourize = 14.681 kJ.

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