In: Statistics and Probability
There are four treatment groups in the experiment, with 13 lizards within each treatment
T1: Brown lizard, brown leaf
T2: Brown lizard, green leaf
T3: Green lizard, green leaf
T4: Green lizard, brown leaf
Is the fitness of green lizards on green leaves higher than expected, based on the individual effects of lizards color and leaf color? Calculate the interactions as the difference between(the overall mean fitness plus the observed lizard fitness in the Green Lizards and Green Leaves treatments), minus (that expected based on the average fitness of Green Lizards plus the average fitness of lizards grown in Green Leaves). Interpret the significance from the results of your statistical test above
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Brown leaves | Green leaves | |
Brown lizard | 8.088210 | 7.157375 |
Green lizard | 9.053549 | 10.004778 |
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Use underneath table to acquire MS and F-statisitc
degree of freedom | Sum of Squares | |
Lizard Color | 1 | 50.880 |
Leaf Color | 1 | 0.001 |
LizardColor:LeafColor(interaction) |
1 | 12.398 |
Residuals | 52 | 97.122 |
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For all F-statistics of LizardColor, LeafColor, and LizardColor:LeafColor(interaction), the critical value of F statisitc is 3.18(alpha = 0.05), and this is 2way ANOVA
degree of freedom | Sum of Squares | MS | F | p-value | |
Lizard Color | 1 | 50.88 | 50.88 | 27.24161 | 3.18263E-06 |
Leaf Color | 1 | 0.001 | 0.001 | 0.000535 | 0.981628035 |
LizardColor:LeafColor(interaction) | 1 | 12.398 | 12.398 | 6.638002 | 0.012861477 |
Residuals | 52 | 97.122 | 1.86773077 | ||
Total | 55 | 160.401 |
The hypothesis being tested is:
H0: There is no main effect of Lizard Color
Ha: There is a main effect of Lizard Color
The p-value is 0.0000.
Since the p-value (0.0000) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is a main effect of Lizard Color.
The hypothesis being tested is:
H0: There is no main effect of Leaf Color
Ha: There is a main effect of Leaf Color
The p-value is 0.9816.
Since the p-value (0.9816) is greater than the significance level (0.05), we fail to reject the null hypothesis.
Therefore, we cannot conclude that there is a main effect of Leaf Color.
The hypothesis being tested is:
H0: There is no interaction effect
Ha: There is an interaction effect
The p-value is 0.01286.
Since the p-value (0.01286) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is an interaction effect.
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