In: Statistics and Probability
QUESTION 5
The variable Z has a standard normal distribution. The probability P(- 0.5 < Z < 1.0) is:
| 
 a.  | 
 0.5328  | 
|
| 
 b.  | 
 0.3085  | 
|
| 
 c.  | 
 0.8413  | 
|
| 
 d.  | 
 0.5794  | 
QUESTION 6
If a random variable X is normally distributed with a mean of 30 and a standard deviation of 10, then P(X=20) =
| 
 a.  | 
 0.4772  | 
|
| 
 b.  | 
 -0.4772  | 
|
| 
 c.  | 
 -2.00  | 
|
| 
 d.  | 
 0.00  | 
QUESTION 7
If P( -z < Z < +z) = 0.8812, then the z-score is:
| 
 a.  | 
 1.56  | 
|
| 
 b.  | 
 1.89  | 
|
| 
 c.  | 
 0.80  | 
|
| 
 d.  | 
 2.54  | 
QUESTION 8
If the mean of a normal distribution is negative,
| 
 a.  | 
 the standard deviation must also be negative.  | 
|
| 
 b.  | 
 the variance must also be negative.  | 
|
| 
 c.  | 
 a mistake has been made in the computations, because the mean of a normal distribution can not be negative.  | 
|
| 
 d.  | 
 None of these alternatives is correct.  | 
QUESTION 9
The starting salaries of individuals with an MBA degree are normally distributed with a mean of $90,000 and a standard deviation of $20,000. What is the probability that a randomly selected individual with an MBA degree will have a starting salary of at least $78,500?
QUESTION 10
The starting salaries of individuals with an MBA degree are normally distributed with a mean of $90,000 and a standard deviation of $20,000. What is the lowest salary for those individuals with an MBA degree whose starting salary is in the top 25 percent?
5)
P(-0.5 < Z < 1) = P(Z < 1) - P(Z < -0.5) = 0.8413 - 0.3085 = 0.5328
6)
mean = 
 = 30
standard deviation = 
 = 10
x = 20
P(x = 20 ) = 0
In continuous distribution the exactly probability is always equal to 0 .
7)
P(-z < Z < z) = 0.8812
P(Z < z) - P(Z < z) = 0.8812
2P(Z < z) - 1 = 0.8812
2P(Z < z) = 1 + 0.8812
2P(Z < z) = 1.8812
P(Z < z) = 1.8812 / 2
P(Z < z) = 0.9406
P(Z < 1.56) = 0.9406
z score = 1.56
8)
None of these alternatives is correct.
9)
mean = 
 = 90000
standard deviation = 
 = 20000
P(x 
 78500) = 1 - P(x  
78500)
= 1 - P((x - 
) / 
(78500 - 90000) / 20000)
= 1 -  P(z 
 -0.58)  
= 1 - 0.2810
= 7190
Probability = 0.7190
10)
P(Z > z) = 25%
1 - P(Z < z) = 0.25
P(Z < z) = 1 - 0.25
P(Z < 0.67) = 0.75
z = 0.67
Using z-score formula,
x = z * 
 + 
x = 0.67 * 20000 + 90000 = 103600
salary = 103600