evaluate P(Z < -0.51)

Expert Solution

From standard normal table, the corresponding area is:

Hence,

P(z < -0.51) = 0.3050

orchestra answered 2 years ago

P(z ≥ −1.26) P(−1.23 ≤ z ≤ 2.64) P(−2.18 ≤ z ≤ 0.96) P(−0.83 ≤ z...

P(z ≥ −1.26) P(−1.23 ≤ z ≤ 2.64) P(−2.18 ≤ z ≤ 0.96) P(−0.83 ≤ z ≤ 0)

find the probabilities for each using the standard normal distribution. p(0<z<0.95), p(0<z<1.96), p(-1.38<z<0), p(z>2.33), p(z<-1.51), p(1.56<z<2.13),...

find the probabilities for each using the standard normal distribution. p(0<z<0.95), p(0<z<1.96), p(-1.38<z<0), p(z>2.33), p(z<-1.51), p(1.56<z<2.13), p(z<1.42)

What percentage of the area under the standard normal curve falls between z = - 0.51...

What percentage of the area under the standard normal curve falls between z = - 0.51 and z = 0

1)What is z0 if P(z > z0) = 0.12 P(z < z0) = 0.2 P(z >...

1)What is z0 if P(z > z0) = 0.12 P(z < z0) = 0.2 P(z > z0) = 0.25 P(z < z0) = 0.3

Find: P(Z < -1.24) and also P( Z > 2.73)

P(z < 2.2)

Compute the center Z of SL2(Z/p)

A) If Z is standard normal, then P(Z < 0.5) is

P( Z<z) =0.1492 what is the answer ?

(a) Find P [Z > 1.26]. (b) Find P [Z > -1.37}. (c) find P[-1.25 (a)...

(a) Find P [Z > 1.26]. (b) Find P [Z > -1.37}. (c) find P[-1.25 (a) Find P [Z > 1.26]. (b) Find P [Z > -1.37}. (c) find P[-1.25<Z<0.37). (d) find z such that P[Z>z]=0.05. (e) find z such that P[-z<Z<z]=0.99. (f) find the value of k such that P[k<Z<-0.18]=0.4197

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