In: Math
11. A manufacturing company produced the following number of units in the last 16 days: 27 28 27 28 27 25 25 28 26 28 26 28 31 30 27 26 (e) How many classes would you recommend? Explain. (f) What class interval do you suggest? Explain. (g) What lower limit would you recommend for the first class? Explain. (h) Organize the information into a frequency distribution and determine the relative frequency distribution. You can do this either by hand or in Excel.
(e)
Number of classes = 7
EXPLANATION: The given data contains only numbers: 25,26,27,28,30,31. Since 29 does not occur, we can provide 0 frequency for 29. Thus weare having 7 classes.
(f) Class interval = 1
EXPLANATION: The difference of the various numbers 26 - 25 = 27 - 26 = 28 - 27 = 29 - 28 = 30 - 29 = 31 -30 = 1
(g Lower limit for the first class = 24.5
EXPLANATION: Lowest value in the data set = 25. All the data points are integers. So, in order avoid overlapping of the varous classes, thelower limit for the firstclass is 24.5
(f) The given raw data is formed as a Frequency Distribution as follows:
FREQUENCY DISTRIBUTION:
Class Interval | Frequency |
24.5 - 25.5 | 2 |
25.5 - 26.5 | 3 |
26.5 - 27.5 | 4 |
27.5 - 28.5 | 5 |
28.5 - 29.5 | 0 |
29.5 - 30.5 | 1 |
30.5 - 31.5 | 1 |
Total = N = | 16 |
From the above Frequency Distribution Relative Frequency Distribution is got as follows:
RELATIVE FREQUENCY DISTRIBUTION:
Class Interval | Frequency |
24.5 - 25.5 | 2/16 = 0.1250 |
25.5 - 26.5 | 3/16 =0.1875 |
26.5 - 27.5 | 4/16 = 0.2500 |
27.5 - 28.5 | 5/16=0.3125 |
28.5 - 29.5 | 0 |
29.5 - 30.5 | 1/16=0.0625 |
30.5 - 31.5 | 1/16=0.0625 |
Total = | 1 |