In: Chemistry
25.00mL of 0.25M of AgNO3 react with 20.00mL of 0.150M of HCl. Find the mass of precipitate.
millimoles of AgNO3 = 25 x 0.25 / 1000 = 6.25 x 10^-3
millimoles of HCl = 20.0 x 0.150 / 1000 = 3 x 10^-3
AgNO3 + HCl ---------------> AgCl + HNO3
1 1 1
6.25x10^-3 3 x 10^-3
here limiting reagent is HCl . because mole ratio is low.
1 mol HCl -------------> 1 mol AgCl
3 x 10^-3 mol HCl -----------> ??
moles of AgCl = 3 x 10^-3 mol
mass of AgCl = 3 x 10^-3 x 143.32 = 0.430 g
mass of precipitate = 0.430 g