In: Statistics and Probability
assuming the length X of a certain unit follows the normal distribution with a mean of 50mm and a standard deviation of 5mm. if a random sample of 21units is taken, find the value C such that probability (sample variance > C)= 0.90
Given that,
mean = = 50 mm
standard deviation = = 5 mm
n = 21
= = 50 mm
= / n = 5 / 21 = 1.09
Using standard normal table,
P(Z > z) = 0.90
= 1 - P(Z < z) = 0.90
= P(Z < z ) = 1 - 0.90
= P(Z < z ) = 0.10
= P(Z < -1.28 ) = 0.10
z = -1.28
Using z-score formula
= z * +
= -1.28 * 1.09 + 50
= 48.60 mm
C = 48.60 mm