Question

In: Math

The below data shows the amount of time (in seconds) that animated Disney movies showed the...

The below data shows the amount of time (in seconds) that animated Disney movies showed the use of tobacco and alcohol. Test the claim that the mean difference in time of tobacco use vs. alcohol use is equal to zero at the 0.1 significance level. You may want to use a spreadsheet to help you solve this problem

  Tobacco Alcohol

56.1 110.9
40.5 70.2
37.2 90.6
49.2 112.8
63.4 202.4
48 93.5
52.3 92.8
52 78.1
40.5 109
39.2 45.5
36.6 44.2
59.2 82.9
46.1 123.8
54.1 102.2
54.7 69.9
41.6 53.1
45 79.5
50.5 69.4
45.6 137.8
63.4 135.4
48 97.6
33.6 145.3
51 65
35.9 81.4
42.9 43.7

Claim: Select an answer p > 0 u ≠ 0 u ≤ 0 p < 0 u > 0 p ≥ 0 p ≤ 0 p ≠ 0 u < 0 p = 0 u ≥ 0 u = 0

which corresponds to Select an answer H1: u > 0 H0: u ≠ 0 H1: u < 0 H0: u ≤ 0 H1: u ≠ 0 H0: u = 0 H0: p ≥ 0

Opposite: Select an answer u < 0 p > 0 p ≤ 0 u = 0 p ≠ 0 u ≠ 0 u ≥ 0 p ≥ 0 u > 0 p = 0 p < 0 u ≤ 0

which corresponds to Select an answer H1: u < 0 H0: u ≠ 0 H1: u ≠ 0 H0: u ≤ 0 H0: p ≥ 0 H0: u = 0 H1: u > 0

The test is: Select an answer / left-tailed / two-tailed / right-tailed

The test statistic is: Select an answer / -6.969 / -7.119 / -6.289 / -6.729 / -6.609  (to 3 decimals)

The Critical Value is: Select an answer / ± 1.711 / ± 1.47 / ± 1.316 / ± 1.36 / ± 1.867  (to 3 decimals)

Based on this we: Select an answer / Fail to reject the null hypothesis/ Reject the null hypothesis

Conclusion There Select an answer ( does / not does ) appear to be enough evidence to support the claim that the mean difference in time of tobacco use vs. alcohol use is equal to zero.

Solutions

Expert Solution

Solution:

Here, we have to use two sample t test for the difference between two population means. The excel outputs for this test is given as below:

t-Test: Two-Sample Assuming Equal Variances

Tobaco

Alcohol

Mean

47.464

93.48

Variance

69.46323

1342.794

Observations

25

25

Pooled Variance

706.1287

Hypothesized Mean Difference

0

df

48

t Stat

-6.1224

P(T<=t) one-tail

8.15E-08

t Critical one-tail

1.299439

P(T<=t) two-tail

1.63E-07

t Critical two-tail

1.677224

t-Test: Two-Sample Assuming Unequal Variances

Tobaco

Alcohol

Mean

47.464

93.48

Variance

69.46323

1342.794

Observations

25

25

Hypothesized Mean Difference

0

df

26

t Stat

-6.1224

P(T<=t) one-tail

8.98E-07

t Critical one-tail

1.314972

P(T<=t) two-tail

1.8E-06

t Critical two-tail

1.705618

Answers based on above outputs are given as below:

Claim: u = 0 which corresponds to H0: u = 0

Opposite: u ≠ 0 which corresponds to H1: u ≠ 0

The test is: two-tailed

The test statistic is: -6.289

The Critical Value is: ± 1.711

Based on this we: Reject the null hypothesis

(Because the test statistic value does not lies between the critical values -1.711 and +1.711.)

Conclusion

There not does appear to be enough evidence to support the claim that the mean difference in time of tobacco use vs. alcohol use is equal to zero.


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