In: Chemistry
The percentage deprotonation of a 0.110 M solution of benzoic acid (a weak, monoprotic acid) is 2.4%. What is the pH of the solution?
Let the acid be represented BH
BH (aq) <----> B- (aq) + H+ (aq)
Initial 0.11 0 0
equilibrium 0.11-X X X
Given X = 2.4 % of HA = ( 2.4/100) x 0.11 = 0.00264 = [H+]
pH= -log [H+]
= -log ( 0.00264) = 2.58