Question

In: Statistics and Probability

Suppose we take a poll (random sample) of 3992 students classified as Juniors and find that...

Suppose we take a poll (random sample) of 3992 students classified as Juniors and find that 2818 of them believe that they will find a job immediately after graduation.

What is the 99% confidence interval for the proportion of Juniors who believe that they will, immediately, be employed after graduation.

  1. (0.694, 0.718)
  2. (0.687, 0.724)
  3. (0.699, 0.713)
  4. (0.692, 0.72)

Solutions

Expert Solution

GIVEN:

Sample size of students classified as juniors

Number of juniors who believe that they will find a job immediately after graduation

FORMULA USED:

The formula for 99% confidence interval for population proportion is,

where

is the sample proportion of juniors who believe that they will find a job immediately after graduation.

is the z critical value at 99% confidence level.

CRITICAL VALUE:

The z critical value at 99% confidence level is .

CALCULATION:

The sample proportion is given by,

The 99% confidence interval for proportion of Juniors who believe that they will, immediately, be employed after graduation is,

The correct answer is . Thus the 99% confidence interval for proportion of Juniors who believe that they will, immediately, be employed after graduation is .

orchestra answered 3 years ago
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