Given: • The solubility of X at 100ºC in water is 18.0 g/100 mL water. •...

Given: • The solubility of X at 100ºC in water is 18.0 g/100 mL water. • The solubility of X at 0ºC in water is 3.6 g/100 mL water. How many mL of boiling water would be required to dissolve 25g of X? If that solution was then cooled down to 0ºC, how many grams of X could then crystallize out? What would be the maximum yield recovery for X?

Expert Solution

solubility at 100ºC = 18.0 g/100 mL

The solubility of X at 0ºC = 3.6 g/100 mL

volume of water needed to boil 25 g ox X

18 g -----------------------------> 100 mL

25 g --------------------------------> ?

volume of water = 100 x 25 / 18

= 138.9 mL

boiling water needed = 138.9 mL -----------------------> ( answer 1)

solubility of 138.9 mL = 138.9 x 3.6 / 100

= 5 g

crystallize out amount = 25 - 5

= 20 g

recovery yield = 5 g

queen_honey_blossom answered 2 years ago

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