A 60.0 kgkg skier on level snow coasts 183 mm to a stop from a speed...

A 60.0 kgkg skier on level snow coasts 183 mm to a stop from a speed of 1.70 m/sm/s .

a)Use the work-energy principle to find the coefficient of kinetic friction between the skis and the snow.

b)Suppose a 72.0 kgkg skier with twice the starting speed coasted the same distance before stopping. Find the coefficient of kinetic friction between that skier's skis and the snow.

Solutions

Expert Solution

Given,

The mass, m = 60 kg

The initial speed, v_i = 1.70 m/s

The distance, d = 183 m

The final speed, v _f = 0

By using work energy theorem,

W = 1/2 * m (v²_f - v²_i)

- f d = (0.5) m(v_f² - v_i²)

We know, f = mg

- mg d = (0.5) m(v_f² - v_i²)

- * g d = (0.5) * (v_f² - v_i²)

- * 9.8 * 183 = 0.5 * (0 - 1.70 ²)

= 1.445 / 1793.4

= 0.00081

The mass, m = 72 kg

The speed, v_i = 2 * 1.70 = 3.4 m/s

- mg d = (0.5) m(v_f² - v_i²)

- * g d = (0.5) * (v_f² - v_i²)

- * 9.8 * 183 = 0.5 * ( 0 - 3.4²)

= 0.0032

genius_generous answered 9 months ago

Next > < Previous

Related Solutions

A 60.0 kg skier is moving at 6.15 m/s on a frictionless, horizontal snow-covered plateau when...

A 60.0 kg skier is moving at 6.15 m/s on a frictionless, horizontal snow-covered plateau when she encounters a rough patch 3.95 m long. The coefficient of kinetic friction between this patch and her skis is 0.330. After crossing the rough patch and returning to friction-free snow, she skis down an icy, frictionless hill 2.95 m high. How fast is the skier moving when she gets to the bottom of the hill? How much internal energy was generated in crossing...

a high speed dart is shot from ground level with a speed of 140 m/s at...

a high speed dart is shot from ground level with a speed of 140 m/s at a angle 30 degrees above the horizontal. 1. What is the speed& direction of the dart after 6 sec if the air resistance is neglected. 2. How high above the projection point is the ball after 6 seconds? 3. What is the horizontal displacement of the dart at that instance.

A projectile is shot from the edge of a cliff 115 mm above ground level with...

A projectile is shot from the edge of a cliff 115 mm above ground level with an initial speed of v0v0 = 65 m/sm/s at an angle of 35.0∘∘ with the horizontal, as shown in the figure (Figure 1). Figure 1 of 1 Part A Determine the time taken by the projectile to hit point PP at ground level. Express your answer to three significant figures and include the appropriate units. tt = nothingnothing SubmitRequest Answer Part B Determine the...

A particle is uncharged and is thrown vertically upward from ground level with a speed of...

A particle is uncharged and is thrown vertically upward from ground level with a speed of 23.1 m/s. As a result, it attains a maximum height h. The particle is then given a positive charge +q and reaches the same maximum height h when thrown vertically upward with a speed of 29.3 m/s. The electric potential at the height h exceeds the electric potential at ground level. Finally, the particle is given a negative charge -q. Ignoring air resistance, determine...

1.) A particle is uncharged and is thrown vertically upward from ground level with a speed...

1.) A particle is uncharged and is thrown vertically upward from ground level with a speed of 20.1 m/s. As a result, it attains a maximum height h. The particle is then given a positive charge +q and reaches the same maximum height h when thrown vertically upward with a speed of 27.3 m/s. The electric potential at the height h exceeds the electric potential at ground level. Finally, the particle is given a negative charge −q. Ignoring air resistance,...

A projectile is launched from ground level at angle θ and speed v_0 into a headwind...

A projectile is launched from ground level at angle θ and speed v_0 into a headwind that causes a constant horizontal acceleration of magnitude a opposite the direction of motion. Find an expression in terms of a and g for the launch angle that gives maximum range. The answer is θ = 45 - (1/2)tan^-1(a/g) The problem that I'm having is I have no idea how to get to that answer. Please do the problem and tell me where you...

A toy rocket is launched vertically from ground level (y = 0 mm), at time t...

A toy rocket is launched vertically from ground level (y = 0 mm), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 80 m and acquired a velocity of 20 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The maximum height reached by the rocket is closest to:

How would you use Path-Goal Theory to stop passive-aggressive behaviors from senior-level employees from destroying the...

How would you use Path-Goal Theory to stop passive-aggressive behaviors from senior-level employees from destroying the morale of junior-level employees?

Please answer 3. 3. The airplane from Problem 2 has a maximum speed in steady level...

Please answer 3. 3. The airplane from Problem 2 has a maximum speed in steady level flight of 190 kts at 8,000 ft altitude. At this condition, the propeller efficiency is 0.75. Presuming a single reciprocating piston engine, and using the simple models for altitude lapse, compute the maximum shaft brake power in hp that the engine can produce at sea level. 2. Consider an airplane with a wing area of 240 ft2 , a span of 44 ft, an...

Subjects