In: Physics
A 60.0 kgkg skier on level snow coasts 183 mm to a stop from a speed of 1.70 m/sm/s .
a)Use the work-energy principle to find the coefficient of kinetic friction between the skis and the snow.
b)Suppose a 72.0 kgkg skier with twice the starting speed coasted the same distance before stopping. Find the coefficient of kinetic friction between that skier's skis and the snow.
Given,
The mass, m = 60 kg
The initial speed, vi = 1.70 m/s
The distance, d = 183 m
The final speed, v f = 0
By using work energy theorem,
W = 1/2 * m (v2f - v2i)
- f d = (0.5) m(vf2 - vi2)
We know, f = mg
- mg d = (0.5) m(vf2 - vi2)
- * g d = (0.5) * (vf2 - vi2)
- * 9.8 * 183 = 0.5 * (0 - 1.70 2)
= 1.445 / 1793.4
= 0.00081
b)
The mass, m = 72 kg
The speed, vi = 2 * 1.70 = 3.4 m/s
- mg d = (0.5) m(vf2 - vi2)
- * g d = (0.5) * (vf2 - vi2)
- * 9.8 * 183 = 0.5 * ( 0 - 3.42)
= 0.0032