Question

Here is the data for our experiment.

a) The data are the SMUT scores of the students in each group. Notice that we have a different number (n) for the lecture group. This is to show you that we can have uneven sets of data for ANOVA. Note: If we were doing a real study, we would have larger n’s. Enter the data into the Excel spread sheet, SPSS or your calculator

Independent Variable	Data
Computer (n1= 8)	85, 87, 91, 78, 90, 83, 86, 89
Lecture (n2= 7)	79, 76, 75, 79, 75, 72, 81,
Cooperative (n3= 8)	80, 99, 87, 84, 83, 77, 76, 80

b) Performing the ANOVA:

Use SPSS, Excel or your calculator to enter the data above and perform a one-way ANOVA. Your spreadsheet should have 2 columns one for the I.V. and one for the D.V. You may create your own variable names. There are 3 nominal levels for the I.V. (1=computer; 2=lecture; 3=cooperative) while your D.V. is a continuous variable.

c) Calculating the F-Score (F-ratio):

The value of F is obtained by dividing the Between Groups Mean Square by the Within Groups Mean Square.

The formula for the F-ratio is F= Vb/Vw = between-groups variance/ Within-groups variance

We divide the variance that can be attributed between the groups by the variance that can be attributed within the groups. If the two variances are the same, the F-ratio will be equal to one. We would thus conclude that no difference exists between the groups because we get the same variance whether we compute the variance between groups or the variance within the groups. As the variance between the groups increases, the value of the F-ratio will increase, if the Within Groups variance remains the same. Likewise, as the Within Groups variance increases, this tends to decrease the value of the F-ratio. Any F- ratio less than or equal to 1 result in a non-significant difference between the population means. That is, a failure to reject the null hypothesis.

d) Once you have entered all the data and run your ANOVA and F-ration, based on the results do you reject the null hypothesis or fail to reject the null hypothesis?

Please I will need help with this assignment. thanks

Answer 1