In: Computer Science
Directions: Convert the following problems below to c++ equivalent code
Problem 3:
3. Add 82 to the number.
4. Remove the hundreds place from your number
5. Add 1 to the number.
6. Subtract this
from your original number (stored in step 2).
7. Output the result obtained
Problem 4:
1. Select two, single digit, numbers, the first being in the range 2 to 6 and the second being in the range 1 to 9.
2. Multiply the first number by five.
3. Add three to that number.
4. Double the number.
5. Add the second number to your previous step.
6. Subtract 6 from the new total and:
The tens place should be the first number given and the ones place should be the second.
#include <iostream>
using namespace std;
int main() {
int num;
// read number
cout << "Enter a two digit number from 31 to 99: ";
cin >> num;
// store copy
int copy = num;
// perform operations
num = num + 82;
num = num % 100;
num = num + 1;
num = copy - num;
// display result
cout << "Result: " << num;
}

#include <iostream>
using namespace std;
int main() {
int n1, n2;
// reading user inputs
cout << "Enter a single digit number between 2 to 6: ";
cin >> n1;
cout << "Enter another single digit number between 1 to 9: ";
cin >> n2;
// storing copy of first number
int copy_n1 = n1;
// perform the operations on copy_n1
copy_n1 = n1 * 5;
copy_n1 = copy_n1 + 3;
copy_n1 = 2 * copy_n1;
copy_n1 = copy_n1 + n2;
copy_n1 = copy_n1 - 6;
// calculate the ones place and store in variable
int ones = copy_n1 % 10;
copy_n1 = copy_n1 / 10;
// calculate the tens place and store in variable
int tens = copy_n1 % 10;
// display the results
cout << "First digit entered is '" << n1 << "' and tens place is also '" << tens << "'" << endl;
cout << "Second digit entered is '" << n2 << "' and ones place is also '" << "'" << ones;
}

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