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A PVT cell consists of n-butane and nitrogen. The settings are set at 19 deg C...

A PVT cell consists of n-butane and nitrogen. The settings are set at 19 deg C and 90 Bar with a volume of 25.38 cc. It is in the vapor-liquid phase. For gas, there is a molar volume of 252.8 cc/mol (55.2%) and n-Butane of 6.3%....If there are 110 moles of n-Butane, how many moles of nitrogen are there and what is the molar volume of liquid?

Solutions

Expert Solution


Pressure of mixture = 90 bars

temperature = 19 0C = 19 + 273 = 292 K

volume = 25.38 cc = 25.38 mL = 25.38 * 10^-3 L

number of moles = PV/RT = (90 * 25.38 * 10^-3)/(0.083*292)

number of moles = 0.09425 moles

0.09425 moles has 25.38 cc volume then

molar volume = 25.38/0.09425 = 269.283 cc/mol

molar volume of mixture = 252.8 mL/mol

110 moles of mixture = (252.8 mL/mol) * (110 mol)

                     = 27808 mL = 27.808 L

volume of n-butane = 27.808 * 55.2/100 = 15.35 L

number of moles of n-butane = PV/RT

                            = 90 * 15.35/(0.083 * 292)

                            = 57.001 moles

volume of nitrogen = 27.808 * 6.3/100 = 1.752 L

number of moles of N2 = 90 * 1.752/(0.083 * 292)

                      = 6.506 moles

queen_honey_blossom answered 2 years ago
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