In: Math
You take a quiz with 6 multiple choice questions. After you studied, you estimated that you would have about an 80% chance of getting any individual question right. What are your chances of getting them all right? The random numbers below represent a simulation with 20 trials. Let 0-7 represent a correct answer and let 8-9 represent an incorrect answer.
1, 6 5 6 2
0 5
2, 4 7 3 1
6 6
3, 5 2 9 6
3 2
4, 8 0 1 6
0 8
5, 3 4 3 3
4 4
6, 2 9 1 7
3 0
7, 6 5 9 6
8 3
8, 8 6 4 4
2 7
9, 6 1 1 8
2 6
10, 5 3 0 3
8 6
11, 0 2 8 1
3 2
12, 6 8 6 0
0 4
13, 9 9 4 6
1 8
14, 1 7 3 2
5 1
15, 7 6 6 1
4 5
16, 3 5 3 1
4 5
17, 0 2 7 7
3 1
18, 3 6 1 6
1 0
19, 8 4 6 7
1 3
20, 5 3 5 2
0 9
Given that
Total no,of questions = 6
Total no.of chances or trials = 20
p = 0.8
q=0.2
The probability of getting all answers correct is
P(X=6) = C(6,6) * (0.8)6 * (0.2)6-6
= 1*0.2621*1
=0.2621
Here in the given table
0.-7 is correct answer
8-9 is incorrect answer
No.of correct answers
1, 6 5 6 2
0 5----------------------- 6
2, 4 7 3 1
6 6----------------------- 6
3, 5 2 9 6
3 2----------------------- 5
4, 8 0 1 6
0 8----------------------- 4
5, 3 4 3 3
4 4----------------------- 6
6, 2 9 1 7
3 0----------------------- 5
7, 6 5 9 6
8 3----------------------- 4
8, 8 6 4 4
2 7----------------------- 5
9, 6 1 1 8
2 6----------------------- 5
10, 5 3 0 3
8 6--------------------- 5
11, 0 2 8 1
3 2--------------------- 5
12, 6 8 6 0
0 4--------------------- 5
13, 9 9 4 6
1 8--------------------- 3
14, 1 7 3 2
5 1--------------------- 6
15, 7 6 6 1
4 5--------------------- 6
16, 3 5 3 1
4 5--------------------- 6
17, 0 2 7 7
3 1--------------------- 6
18, 3 6 1 6
1 0--------------------- 6
19, 8 4 6 7
1 3--------------------- 5
20, 5 3 5 2
0 9--------------------- 5
Total - 104
Or you can also count how many 8's and 9's in the above table and just subtract from 120.
There are 16 (8's and 9's). So 120-16 = 104
The chance of getting all the answers correct = 104/120 = 0.867 = 86.7%