Question

public static char mostFrequent(String str) {
       if(str.length()==0) {
           return '0';
       }
       String temp="";
       for (int i = 0; i < str.length(); i++) {
                if(!temp.contains(String.valueOf(str.charAt(i)))) {
                    temp += String.valueOf(str.charAt(i));
                }
            }
       char[] tempArray=stringToArray(temp);
       int[] countArr=new int[tempArray.length];
       int max=0;
       for(int i=0;i<tempArray.length;i++) {
           int cnt=numOccurences(tempArray[i],str);
           countArr[i]=cnt;
           if(max<cnt) {
               max=cnt;
           }
       }
       for(int i=0;i<tempArray.length;i++) {
           if(max==countArr[i]) {
               return tempArray[i];
           }
       }
       return '0';
      }

CAN SOMEONE PLEASE COMMENT OUT THIS CODE, I DON'T KNOW EXACTLY WHAT IT DOES, THANKS.

Answer 1

below is well commented code
This code basically returns the character in string having maximum frequency.

public static char mostFrequent(String str) {
//check if string length is zero, then return 0 as answer
if(str.length()==0) {
return '0';
}
String temp="";
// this loop basically adds all the unique characters of str to temp
for (int i = 0; i < str.length(); i++) {
// checks if a char is in temp or not, if not add it to temp
if(!temp.contains(String.valueOf(str.charAt(i)))) {
temp += String.valueOf(str.charAt(i));
}
}
// convert string into char array
char[] tempArray=stringToArray(temp);
// new count array of integer
int[] countArr=new int[tempArray.length];
int max=0;
for(int i=0;i<tempArray.length;i++) {
// count occurence of each character in str
int cnt=numOccurences(tempArray[i],str);
countArr[i]=cnt;
//update maximum count
if(max<cnt) {
max=cnt;
}
}
for(int i=0;i<tempArray.length;i++) {
//return element with maximum count
if(max==countArr[i]) {
return tempArray[i];
}
}
return '0';
}
Thank you, please upvote