In: Math
A Pew Research Center survey asked respondents if they would rather live in a place with a slower pace of life or a place with a faster pace of life. The survey also asked the respondent’s gender. Consider the following sample data.
Gender | ||||
Preferred Pace of Life | Male | Female | ||
---|---|---|---|---|
Slower | 232 | 218 | ||
No Preference | 19 | 25 | ||
Faster | 89 | 47 |
a. Is the preferred pace of life independent of gender? Using a level of significance, what is the -value?
Compute the value of the test statistic (to 3 decimals).
The -value is - Select your answer -between .01 and .025between .025 and .05between .05 and .10greater than .10less than .01Item 2
What is your conclusion?
- Select your answer -Cannot concludeConcludeItem 3 that the preferred pace of life is not independent of gender.
b. What are the percentage responses for each gender (to 1 decimal)?
Gender | ||
Preferred Pace of Life | Male | Female |
---|---|---|
Slower | ||
No Preference | ||
Faster |
Discuss any differences between the preferences of men and women.
- Select your answer -Men onlyWomen onlyBoth men and womenItem 10 prefer a slower pace of life. Women have a higher preference for a - Select your answer -slowerfasterItem 11 pace of life, while men have a higher preference for a - Select your answer -slowerfasterItem 12 pace of life.
Solution:
Here, we have to use chi square test for independence of two categorical variables.
Null hypothesis: H0: The preferred pace of life is independent of gender.
Alternative hypothesis: Ha: The preferred pace of life is not independent of gender.
We are given level of significance = α = 0.05
Test statistic formula is given as below:
Chi square = ∑[(O – E)^2/E]
Where, O is observed frequencies and E is expected frequencies.
E = row total * column total / Grand total
We are given
Number of rows = r = 3
Number of columns = c = 2
Degrees of freedom = df = (r – 1)*(c – 1) = 2*1 = 2
α = 0.05
Critical value = 5.991465
(by using Chi square table or excel)
Calculation tables for test statistic are given as below:
Observed Frequencies (O) |
|||
Gender |
|||
Preferred Pace of Life |
Male |
Female |
Total |
Slower |
232 |
218 |
450 |
No Preference |
19 |
25 |
44 |
Faster |
89 |
47 |
136 |
Total |
340 |
290 |
630 |
Expected Frequencies (E) |
|||
Gender |
|||
Preferred Pace of Life |
Male |
Female |
Total |
Slower |
242.8571 |
207.1429 |
450 |
No Preference |
23.74603 |
20.25397 |
44 |
Faster |
73.39683 |
62.60317 |
136 |
Total |
340 |
290 |
630 |
(O - E) |
|
-10.8571429 |
10.85714286 |
-4.74603175 |
4.746031746 |
15.6031746 |
-15.6031746 |
(O - E)^2/E |
|
0.485378151 |
0.569064039 |
0.948571853 |
1.112118724 |
3.317024359 |
3.88892511 |
Chi square = ∑[(O – E)^2/E] = 10.32108
P-value = 0.005739
(By using Chi square table or excel)
P-value < α = 0.05
P-value is less than 0.01.
So, we reject the null hypothesis
There is sufficient evidence to conclude that the preferred pace of life is not independent of gender.
Part b
Required percentages for each gender are given as below:
Observed Frequencies (O) |
||
Gender |
||
Preferred Pace of Life |
Male |
Female |
Slower |
68.2% |
75.2% |
No Preference |
5.6% |
8.6% |
Faster |
26.2% |
16.2% |
Total |
100.0% |
100.0% |
From above table, it is observed that both men and women prefer a slower pace of life.