In: Math
An educational psychologist has developed a mediation technique
to reduce anxiety. The psychologist selected a sample of high
anxiety students that are asked to do the mediation at two therapy
sessions a week apart. The participants' anxiety is measured the
week before the first session and at each subsequent session. Below
are the anxiety scores for the participants. What can the
psychologist conclude with α= 0.05?
before | session 1 | session 2 |
---|---|---|
9 6 8 5 8 6 9 6 8 |
7 7 6 7 1 9 7 7 7 |
6 5 5 4 5 6 5 5 4 |
Make an interpretation based on the results.
At least one of the sessions differ on anxiety.None of the sessions differ on anxiety.
e) Conduct Tukey's Post Hoc Test for the following
comparisons:
2 vs. 3: difference = ;
significant: ---Select--- Yes No
1 vs. 2: difference = ;
significant: ---Select--- Yes No
f) Conduct Scheffe's Post Hoc Test for the
following comparisons:
1 vs. 3: test statistic = ;
significant: ---Select--- Yes No
2 vs. 3: test statistic = ;
significant: ---Select--- Yes No
before | session 1 | session 2 | Anova: Single Factor | |||||||
9 | 7 | 6 | ||||||||
6 | 7 | 5 | SUMMARY | |||||||
8 | 6 | 5 | Groups | Count | Sum | Average | Variance | |||
5 | 7 | 4 | Before | 9 | 65 | 7.222222 | 2.194444 | |||
8 | 1 | 5 | Session 1 | 9 | 58 | 6.444444 | 4.777778 | |||
6 | 9 | 6 | Session 2 | 9 | 45 | 5 | 0.5 | |||
9 | 7 | 5 | ||||||||
6 | 7 | 5 | ||||||||
8 | 7 | 4 | ANOVA | |||||||
Source of Variation | SS | df | MS | F | P-value | F crit | ||||
Between Groups | 22.88889 | 2 | 11.44444 | 4.594796 | 0.020441 | 3.402826 | ||||
Within Groups | 59.77778 | 24 | 2.490741 | |||||||
Total | 82.66667 | 26 |
From ANOVA table we see that P-value=0.020441<0.05 so there is sufficient evidence that at least one of the sessions differ on anxiety.