Question

In: Statistics and Probability

The Travel Channel wants to conduct a survey of adults who take weekend vacations to Las...

The Travel Channel wants to conduct a survey of adults who take weekend vacations to Las Vegas. If the channel wants to be 97% confident that the sample percentage is in error by no more than 1.75 percentage points, how many adults must be surveyed?

Solutions

Expert Solution

Solution :

Given that,

= 0.5 ( assume 0.5)

1 - = 1 - 0. 5= 0.5

margin of error = E = 0.0175

At 97% confidence level the z is ,

= 1 - 97% = 1 - 0.97 = 0.03

/ 2 = 0.015

Z/2 = Z0.015 = 2.17 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= ( 2.17/ 0.0175)2 * 0.5 * 0.5

= 3844

Sample size =3844


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