Question
In: Statistics and Probability
A survey is done to estimate the proportion of US Adults who think that texting while...
A survey is done to estimate the proportion of US Adults who think that texting while driving should be illegal. In a survey, 82% of a randomly selected sample of 1025 individuals said that this should be illegal.
q1: A 95% confidence interval is construct to estimate the proportion, the STANDARD ERROR is 0.012. What is the margin of error?
Solutions
Expert Solution
Solution :
Given that,
n = 1025
Point estimate = sample proportion = 
= 82%=0.82
1 -
= 1-0.82 =0.18
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2
= Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z
/2 *
* (1 -
)) / n)
= 1.96 *STANDARD ERROR
= 1.96*0.012
margin of error =0.02352
orchestra answered 2 years agoRelated Solutions
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