In: Finance
A borrower takes out a 30-year mortgage loan for $250,000 with an interest rate of 6% and monthly payments. What portion of the first month's payment would be applied to interest? ($1250) Assume the question above was a negative amortization loan, what would be the balance after 3 years?
a. | First month payment applied to interest | $ 1,250.00 | |||||||
Working: | |||||||||
Interest expense | = | Loan balance at the beginning | * | Monthly interest rate | |||||
= | $ 2,50,000.00 | * | 6%*1/12 | ||||||
= | $ 1,250.00 | ||||||||
b. | Balance after 3 years | $ 2,40,210.18 | |||||||
Working: | |||||||||
Present value of annuity of 1 for 360 months | = | (1-(1+i)^-n)/i | Where, | ||||||
= | (1-(1+0.005)^-360)/0.005 | i | = | 6%/12 | = | 0.005 | |||
= | 166.7916144 | n | = | 30*12 | = | 360 | |||
Monthly payment | = | Loan amount | / | Present value of annuity of 1 | |||||
= | $ 2,50,000.00 | / | 166.7916 | ||||||
= | $ 1,498.88 | ||||||||
Present value of annuity of 1 for 324 months | = | (1-(1+i)^-n)/i | Where, | ||||||
= | (1-(1+0.005)^-324)/0.005 | i | = | 6%/12 | = | 0.005 | |||
= | 160.2601717 | n | = | 30*12 | = | 360 | |||
Balance after 3 years | = | Monthly payment | * | Present value of annuity of 1 for 324 months | |||||
= | $ 1,498.88 | * | 160.2602 | ||||||
= | $ 2,40,210.18 |