In: Chemistry
An average pool is 45 m long and 43 m wide. How many mL of water is required to fill the pool to an average depth of 3.10 ft? Put answer in scientific notation.
convert depth = 3.1 ft in to m
1 ft = 0.3048 m
then 3.1ft = 3.1 * 0.3048 m = 0.9449 m
volume of the pool = length * width * depth
= 45 m * 43 m * 0.9449 m
= 1828.38 m^3
1 m^3 = 1000 L
1828.38 m^3 = 1828.38 * 1000 L
volume of water = 1828.38 * 1000 * 1000 mL
= 1.8283 * 10^9 mL
= 1.83 * 10^9 mL in scintific notation