Question

In: Chemistry

An average pool is 45 m long and 43 m wide. How many mL of water...

An average pool is 45 m long and 43 m wide. How many mL of water is required to fill the pool to an average depth of 3.10 ft? Put answer in scientific notation.

Solutions

Expert Solution

convert depth = 3.1 ft in to m

1 ft = 0.3048 m

then 3.1ft = 3.1 * 0.3048 m = 0.9449 m

volume of the pool = length * width * depth

                                  = 45 m * 43 m * 0.9449 m

                                  = 1828.38 m^3

1 m^3 = 1000 L

1828.38 m^3 = 1828.38 * 1000 L

volume of water = 1828.38 * 1000 * 1000 mL

                             = 1.8283 * 10^9 mL

                             = 1.83 * 10^9 mL in scintific notation


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