Question

In: Statistics and Probability

1:) The dataset shows 15 observations of the relationship between cricket chirps (measured in chirps per...

1:)

The dataset shows 15 observations of the relationship between cricket chirps (measured in chirps per second) and outside ground temperature (in Fahrenheit).

A. Create a scatterplot by putting chirps on the vertical axis and temperature on the horizontal axis. Be sure to properly label the scatterplot with a title, axes titles, and the proper units of the variables.

B. Estimate the following relationship: ?h????=?0+?1???????????(Chirps) ̂=b_0+b_1 Temperature.

C. Interpret the slope in the context of the problem.

D. Interpret the R-square in the context of the problem.

E. Predict the number of cricket chirps when the outside ground temperature is 80 degrees F.   Round your answer to one decimal place.

Data set:

Temperature Chirps
88.6 20
71.6 16
93.3 19.8
84.3 18.4
80.6 17.1
75.2 15.5
69.7 14.7
71.6 15.7
69.4 15.4
83.3 16.3
79.6 15
82.6 17.2
80.6 16
83.5 17
76.3 14.4

Solutions

Expert Solution

This problem is solved by using R

1.The dataset shows 15 observations of the relationship between cricket chirps (measured in chirps per second) and outside ground temperature (in Fahrenheit).

Ans: correlation between cricket chirps and temperature is 0.83 So we conclude there is incresing linear relationship exist.

This relationship can be observed in scatter plot also.

B.. Estimate the following relationship: ?h????=?0+?1???????????(Chirps) ̂=b_0+b_1 Temperature.

Chirps = 0.4593 + 0.2030 temperature

C.Interpret the slope in the context of the problem.

Answer : slope = 0.2030 indicates that chirps prediction value increase by 0.2030 if temperature goes up by 1 degree Fahrenheit.

D.Interpret the R-square in the context of the problem.

Answer : R - squqre = 0.6923

R- square value indicates how good the model fitted. For this problem R sqaure value near to 0.70 so we may conclude fitted model is good.

E.Predict the number of cricket chirps when the outside ground temperature is 80 degre

Answer :

Chirps = 0.4593 + 0.2030* 80

Chirps =16.69

Chirps = 16.7

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