Question

In: Statistics and Probability

The university would like to conduct a study to estimate the true proportion of all university...

The university would like to conduct a study to estimate the true proportion of all university students who have student loans. According to the study, in a random sample of 215 university students, 86 have student loans. (a) Construct a 99% confidence interval for estimating the true proportion of all university students who have student loans (b) Provide an interpretation of the confidence interval in part (a). (1mark) (c) Conduct an appropriate hypothesis test, at the 1% level of significance to test the claim that more than 30% of all university students have student loans. Provide the hypothesis statement Calculate the test statistic value Determine the probability value

Solutions

Expert Solution

(a) Construct a 99% confidence interval for estimating the true proportion of all university students who have student loans (2 marks)

(b) Provide an interpretation of the confidence interval in part (a). (1mark)
We are 95% confident that the true proportion of the population of the students who have taken the loan is (0.314, 0.486)


(c) Conduct an appropriate hypothesis test, at the 1% level of significance to test the claim that more than 30% of all university students have student loans. Provide the hypothesis statement (1 Marks) Calculate the test statistic value (2 Marks) Determine the probability value (1 Marks)

Hence we can conclude that there is sufficient evidence that more than 30% of all university students have student loans


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