Question

In: Statistics and Probability

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are...

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]

Compute the probability that a randomly selected peanut M&M is not yellow.



Compute the probability that a randomly selected peanut M&M is green or yellow.



Compute the probability that two randomly selected peanut M&M’s are both red.



If you randomly select five peanut M&M’s, compute that probability that none of them are green.



If you randomly select five peanut M&M’s, compute that probability that at least one of them is green.

Solutions

Expert Solution

The probability that randomly selected peanut is yellow will be 0.15 so the probability that randomly selected Peanut is not Yellow will be

P(not Yellow) = 1 - P(Yellow) = 1 - 0.15 = 0.85

Answer: 0.850

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The probability that a randomly selected peanut M&M is green or yellow is

P(green or yellow) = P(green) + P(yellow) = 0.15 + 0.15 = 0.30

Answer: 0.300

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The probability that two randomly selected peanut M&M’s are both red is

P(both red) = P(red) * P(red) = 0.12* 0.12 = 0.0144

Answer: 0.014

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From given information:

P(not Green) = 1 - P(Green) = 1 - 0.15 = 0.85

The probability that none of five are green is

Answer: 0.444

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From the complement rule, the probability that at least one of them is green is

Answer: 0.556

orchestra answered 1 year ago
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