Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select five peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)

Compute the probability that exactly four of the five M&M’s are orange.

Compute the probability that three or four of the five M&M’s are orange.

Compute the probability that at most four of the five M&M’s are orange.

Compute the probability that at least four of the five M&M’s are orange.

Answer 1

Solution:

Given that,

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green.

So, Probability (Orange) = 0.23

The probability that exactly four of the five M&M’s are orange = 0.0108

The probability that three or four of the five M&M’s are orange = 0.0829

The probability that at most four of the five M&M’s are orange = 0.9994

The probability that at least four of the five M&M’s are orange = 0.0114

Explanation:

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