In: Statistics and Probability
From a population of 10,000 students, an average height of 174.5 cm and a standard deviation of 6.9 cm. A sample of 50 is drawn students. What is the expected number of students in the sample whose height varies between 173 cm and 175 cm?
Solution:
We are given
n = 50
µ = 174.5
σ = 6.9
First we have to find P(173<Xbar<175)
P(173<Xbar<175) = P(Xbar<175) - P(Xbar<173)
Find P(Xbar<175)
Z = (Xbar - µ)/(σ/sqrt(n))
Z = (175 - 174.5)/(6.9/sqrt(50))
Z = 0.512396
P(Z<0.512396) = P(Xbar<175) = 0.695813
(by using z-table)
Now find P(Xbar<173)
Z = (Xbar - µ)/(σ/sqrt(n))
Z = (173 - 174.5)/(6.9/sqrt(50))
Z =-1.53719
P(Z<-1.53719) = P(Xbar<173) = 0.062124
(by using z-table)
P(173<Xbar<175) = P(Xbar<175) - P(Xbar<173)
P(173<Xbar<175) = 0.695813 - 0.062124
P(173<Xbar<175) = 0.633689
Expected number of students = n* P(173<Xbar<175) = 50*0.633689 = 31.68445
The expected number of students in the sample is Approximately 32 students whose height varies between 173 cm and 175 cm.