Question
In: Civil Engineering
when calculating the moment of a trianglular distrubted load the answers always seem to be in...
when calculating the moment of a trianglular distrubted load the
answers always seem to be in some form of a cubic (x^3) however
when I work the problem out I only come up with x^2, the x-terms
coming from (xh/2) and (x/3) or (2x/3), where does the x^3 come
from?
Solutions
Ally Wells answered 1 year agoRelated Solutions
Fixed load bending moment MD = 130 kN·m, live load bending moment ML = 140 kNNm...
Fixed load bending moment MD = 130 kN·m, live load bending
moment ML = 140 kNNm
Rectangular short beams with width b = 400 mm and depth h = 600 mm
are designed as follows:
Determine design suitability. Assume the coating thickness is 40
mm.(f ck = 27 MPa, f y = 300 MPa , tensile reinforcement 6-D22,
shear reinforcement D10)
Fixed load bending moment MD = 130 kN·m, live load bending moment ML = 140 kNNm...
Fixed load bending moment MD = 130 kN·m, live load bending
moment ML = 140 kNNm
Rectangular short beams with width b = 400 mm and depth h = 600 mm
are designed as follows:
Determine design suitability. Assume the coating thickness is 40
mm.(f ck = 27 MPa, f y = 300 MPa , tensile reinforcement 6-D22,
shear reinforcement D10)
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